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4500=180x^2
We move all terms to the left:
4500-(180x^2)=0
a = -180; b = 0; c = +4500;
Δ = b2-4ac
Δ = 02-4·(-180)·4500
Δ = 3240000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3240000}=1800$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1800}{2*-180}=\frac{-1800}{-360} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1800}{2*-180}=\frac{1800}{-360} =-5 $
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